While performing a neutralization reaction, Jonna added 22.63 mL of 0.142 M H2SO4 to 46.21 mL of 0.304 M KOH. How many moles of OH- are unreacted in the solution after the neutralization is complete?

7.623 x 10⁻³ mol OH⁻

Explanation:

The reaction that takes place is:

Now we calculate how many moles of each reagent were added:

We calculate how many OH⁻ moles reacted with H₂SO₄:

Finally we substract the OH⁻ moles that reacted from the added ammount of OH⁻ moles:

did anyone actually do this? like if anyone has submitted this i rly need .

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml