What pressure is required to compress 200 liters of air at 100 atmosphere into a cylinder whose volume is 20.0 liters?

P₂ = 1000 atm

Explanation:

Given data:

Initial volume of air = 200 L

Initial pressure = 100 atm

Final volume = 20.0 L

Final pressure required = ?

Solution:

The given problem will be solved through the Boly's law,

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

100 atm × 200 L= P₂  × 20.0 L

P₂ = 20,000 atm. L/ 20.0 L

P₂ = 1000 atm

consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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