How to write the ionic formula for the K1+, MnO41- pair of ions

Ionic formula: KMnO4

Explanation:

Pottasium permanganate (KMnO4) is an ionic compound that contains a combination of pottasium cations (K+) and permanganate anion (MnO4-). The pair of ions that make up the ionic compound cancel out each other to make it neutral.

K+ (aq) + MnO4- (aq) → KMnO4 (aq)

MnO4- contains 1 atom of manganese with a (+7) charge and four atoms of oxygen with a (-2) charge each. This forms a +7 for Mn and -8 for O4, hence, a net total of -1.

(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied

considering the question as per the attachment

here we can see that the radon nuclide has 222 as the atomic mass number and 86 as the atomic number.

when it undergoes nuclear fission it gives polonium which has atomic mass number as 218 and atomic number will be 84 along with a helium nucleus which has 4 atomic mass number and 2 as its atomic number.

222 = 218 + 4 (atomic mass number)

86 = ? + 2; therefore ? = 86-2 = 84.

the atomic mass number of polonium will be 84.