Determine the empirical formula of a compound containing 47 37 grams of carbongrams of hydrogen, and of oxygen In an expenmen the me compound was determined to de 228 276 gis the molecular of the compound? For both questions your work or explain how you detemined the formulas by giving specille values used in calculations

Molecular formula :  C₉H₂₄O₆

Determine the empirical formula of a compound containing 47.37 grams of carbon, 10.59 grams of hydrogen, and 42.04 grams of oxygen. In an experiment, the molar mass of the compound was determined to be 228.276 g/mol. What is the molecular formula of the compound? For both questions, show your work or explain how you determined the formulas by giving specific values used in calculations.

mol of C :

mol of H :

mol of O :

divide by smallest (2.6275)

C : H : O ⇒

Empirical formula(EF) : C₃H₈O₂

(EF)n=MF(molecular formula)

( C₃H₈O₂)n=228.276

(3x12.0107+8x1,00784+2x15,999)n=228.276

(76.09282)n=228.276⇒n≈3

Molecular formula : C₉H₂₄O₆

a  solution  is always transparent, light passes through with no scattering from solute particles which are molecule in size. the  solution  is homogeneous and does not settle out. a colloid is intermediate between asolution  and a  suspension. while asuspension  will separate out a colloid will not.