Calculate the volume of one mole of a gas at 1.00 atm pressure and 0 °C.

Solution:-

The gas is in the standard temperature and pressure condition i.e. at S.T.P

Therefore,

V

i

=22.4dm

3

V

f

=?

As given that the expansion is isothermal and reversible

∴ΔU=0

Now from first law of thermodynamics,

ΔU=q+w

∵ΔU=0

∴q=–w

Given that the heat is absorbed.

∴q=1000cal

⇒w=−q=−1000cal

Now,

Work done in a reversible isothermal expansion is given by-

w=−nRTln(

V

i

V

f

)

Given:-

T=0℃=273K

n=1 mol

∴1000=−nRTln(

V

i

V

f

)

⇒1000=−1×2.303×2×273×log(

22.4

V

f

)

Explanation:

with this one i know the answer in craters one reason i looked it up and i learned about it there is my evidence

> b takes place in the gas phase in an isothermal tubular reactor. the feed is one mole of a per one mole of c, an inert. the entering temperature and pressure are 427°c and 10 atm, respectively. the gas constant r = 0.08206 atm · l/mol · k.