How many moles of gas occupy 98 l at a pressure of 2.8 atmosphere and a temperature of 292

n = 11.45 mol

Explanation:

Given data:

Number of moles = ?

Volume of gas = 98 L

Pressure = 2.8 atm

temperature = 292 K

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

2.8 atm × 98 L = n × 0.0821 atm.L/ mol.K   × 292 K

274.4 atm.L = n ×  23.97atm.L/ mol

n = 274.4 atm.L /23.97atm.L/ mol

n = 11.45 mol

the answer is 0.8m.

by: nicholas

hey there!

mass = 6.75 g

volume =   9 cm³

therefore:

d = mass / volume

d   = 6.75 / 9

d = 0.7 g/cm³

answer b