At 303 K, the volume of a gas is 30.0 ml. At constant pressure, what is the new volume of the gas if the temperature is decreased to 283K?

V₂ = 28 mL

Explanation:

Given data:

Initial temperature = 303 K

Initial volume = 30.0 mL

Final temperature = 283 K

Final volume = ?

Solution:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 30.0 mL × 283 K /303 K

V₂ = 8490 mL.K / 303 K

V₂ = 28 mL

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