Which equation shows how to calculate how many grams (g) of KOH would be needed to fully react with 4 mol Mg(OH)2? The balanced reaction is:
MgCl2 + 2KOH → Mg(OH)2 + 2KCI

A.

General Formulas and Concepts:

Chemistry - Stoichiometry

Explanation:

Step 1: Define

Given:   4 mol Mg(OH)₂

RxN:   MgCl₂ + 2KOH → Mg(OH)₂ + 2KCl

Step 2: Identify Conversions

Molar Mass of K - 39.10 g/mol

Molar mass of O - 16.00 g/mol

Molar mass of H - 1.01 g/mol

Molar Mass of KOH - 39.10 + 16.00 + 1.01 = 56.11 g/mol

Step 3: Stoichiometry

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