How many grams of NH3 can be produced from 4.89 mol of N2 and excess H2.

166.56g of NH3 are produced

Explanation:

The reaction of N2 with H2 to produce NH3 is:

N2 + 3H2 → 2NH3

Where 1 mole of N2 produce 2 moles of NH3

4.89 moles of N2 with excess of H2 produce:

4.89 moles N2 * (2 moles NH3 / 1 mole N2) = 9.78 moles NH3

As molar mass of NH3 is 17.031g/mol, mass of NH3 produced is:

9.78 moles * (17.031g / mol) =

answers: to make sure that all of the broken pieces of tablet were added to the water, to allow for fair comparison of all three trials, with different particle sizes to avoid experimental error