1. A gas at 116 kPa and 303 K fills a container at 2.0 x 105 L. If the temperature changes to 293 K, What is the new pressure?

P₂ = 112.17 KPa

Explanation:

Given data:

Initial pressure = 116 KPa

Initial temperature = 303 K

Final temperature = 293 L

Final pressure = ?

Volume=  constant

Solution:

According to Gay-Lussac Law,

The pressure of given amount of a gas is directly proportional to its temperature at constant volume and number of moles.

Mathematical relationship:

P₁/T₁ = P₂/T₂

Now we will put the values in formula:

116 KPa / 303 K = P₂/293 K

P₂ = 116 KPa × 293 K  / 303 K

P₂ = 33988 KPa. K / 303 K

P₂ = 112.17 KPa

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.