The standard molar heat of vaporization for water is 40.79 kj/mol. how much energy would be required to vaporize 30.0g of water? answer in units of kj

The energy of vaporizing one mol is 40.79. 1 mol of water is 18g so the number of moles you have is 30/18. Once you know the number of moles you will need to multiply by the heat of vaporization per mole. Also water is not exactly 18g/mol so you might have to calculate it to a couple decimal places depending on what your teacher wants.

A. 17 hope this dudet