1 mole of ethanol was mixed with 1 mole of ethanoic acid in a 1dm3 container and the following reaction took place
C2H5OH (1) + CH3COOH (1) CH3COOC2H5 (1) + H2O (1)
It was found that 0.66 moles of ethyl ethanoate was formed. Calculate Kc for
this reaction.
C2H5OH (1)
CH3COOH (1) CH3COOC2H5
(1)
H2O (1)
Initial [ ]
Ratio
Reacted []
Equilibrium [ ]
Hence

answer : (a) volume of the gas = 8.67 ×   l

                (b) second virial coefficient b = -1.21226 l/mole

solution :   given,     t = 300k

                                p = 20atm

                                z = 0.86

                                n = 8.2 mmoles = 8.2 × moles

                                r =   0.082 l atm/k/mol

        find,     (a) volume of gas   and (b) second virial coefficient b at 300k.

formula used :            

                          and            

(a)            

                    = \times 0.082\times 300}{20}[/tex]

                    = 8.67 ×   l

(b)      

                    = (0.00867-1) × 8.659

                    = - 8.5839 l/mole

on passing the small ampere of electric current through the tube made of ar and hg of cfl generates uv rays which excites the fluorescent and thus emits the high radiation by consumption of just 5- 12 w in comparison to incandescent light which requires more power such as around 40 - 55 w to lighten.

moreover the life span of fluorescent or cfl is around 8000 h whereas the life span of incandescent is around 1200 h

hence, the building installed with incandescent lights bears more electricity bill.