4. Chemical formula, mg (Cl0₃)2 a) calculate the number of moles for 3.24g, Mg (Cl03)2
b) calculate the molarity of mg (Cl03)2 if all of it were dissolved in
5.08 L distilled water.

0.017mole

0.0033M

Explanation:

Given parameters:

Formula of the compound:

           Mg(ClO₃)₂

Mass of the sample  = 3.24g

Unknown:

Number of moles of the sample = ?

Molarity  = ?

Solution:

The number of moles of any substance is given as:

   Number of moles  =  

 Molar mass of Mg(ClO₃)₂  = 24 + 2[35.5 + 3(16)]  = 191g/mol

    Number of moles  =   = 0.017mole

Molarity is the number of moles of a solute in a solution:

    Molarity  =  

 Volume given  = 5.08L

  Molarity  =  = 0.0033M

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

sorry i was late, but i don't know what assignment your talking about, i'm in flvs as well, im in earth space science. but u are behind pace bc every class should be in the 3's or 4'