What is the total number of Joules lost when 10. grams of water at 80.°C is cooled to 60.°C?

The total number of Joules lost to the surrounding is  -837.2 J

Explanation:

Given that:

mass = 10 grams

initial temperature =  80°C

Final temperature = 60 °C

Specific heat of water= c = 4.186 J/g. °C

The total number of Joules lost can be determined by finding the amount of heat energy Q released by using the formula:

Q = mC ΔT

Q = 10 × 4.186 × (60 - 80)° C

Q = 10 × 4.186 × - 20° C

Q = -837.2 J

Thus, the total number of Joules lost to the surrounding is  -837.2 J

b

explanation:

mitosis

your answer is c) plasma

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