The reaction described in part a required 3.98l of calcium chloride. what is the concentration of this calcium chloride solution?

You need to find the moles of CaCl, you can either do a grams to mol conversion, OR, you can do the equation used in A without the last step which was converting it into the grams on CaCl. You get .00848146 mol CaCl. with that you can find the concentration using the molarity equation which is M=mol/L. M=.000848146mol/3.98 L. M=0.000213 or your teacher may want you to write it 0.000213 M CaCl. Hope I helped :)

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