A 30 gram ball is at rest. Next, a force pushes the ball to the north for 2.5 seconds and the ball accelerates for a rate of 0,70 m/s/s. How fast is the ball going after the 2.5 seconds of acceleration? For credit, who work in detail

1.75m/s or 6.3km/hr

Explanation:

here,

acceleration (a) = 0.7m/s^2

mass (m) = 30g

time (t) = 2.5s

initial velocity (u) = 0m/s

final velocity (v) = ?

now,

v = u + at

or, v = 0 + 0.7 * 2.5

hence, Final velocity (v) = 1.75 m/s

if u want to convert to km/hr

then,

1.75 * 3.6 (we know that 1m/s = 3.6km/hr)

= 6.3km/hr

i do not get it   at all

the cold front replaces the warmer air at the ground level changing the wind to be breezy and denser.there is also an immediate drop in the temperature.