Calculate Ecell for the reaction below 2AgBr(aq) + 2Hg(l) --> 2Ag(s) + Hg2Br2(s)

given the following standard reduction potentials

Hg2Br2(s) + 2e- --> 2Hg(l) + 2Br-(aq) E = +0.140 V

AgBr(aq) + e- --> Ag(s) + Br-(aq) E = +0.071 V

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Answerδh > 0explanationc₆h₆  (s)  → c₆h₆ (l)if you are changing it from a solid to a liquid, you are pretty much melting the solid. this requires heat energy. therefore, the reaction is endothermic (takes in energy); the system enthalpy increases as the reaction proceeds: δh > 0.