Complete the following nuclear bombardment equation by filling in the nuclear symbol for the missing species. ²³⁵₉₂U + ¹₀n → ? + ¹³⁹₅₄Xe + 3 ¹₀n

The missing species in the equation is ⁹⁴₃₈Sr

Let the missing species be ᵇₐY

We can write the equation as:

²³⁵₉₂U + ¹₀n → ᵇₐY + ¹³⁹₅₄Xe + 3¹₀n

235 + 1 = b + 139 + 3(1)

236 = b + 139 + 3

236 = b + 142

Collect like terms

236 – 142 = b

92 + 0 = a + 54 + 0

92 = a + 54

Collect like terms

92 – 54 = a

b = 94

a = 38

ᵇₐY => ⁹⁴₃₈Y => ⁹⁴₃₈Sr

The balanced equation is:

²³⁵₉₂U + ¹₀n → ⁹⁴₃₈Sr + ¹³⁹₅₄Xe + 3¹₀n

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Strontium Sr

Explanation:

By the law of mass conversion the nuclear mass remains constant in a reaction which means initial mass and atoic number will be equal to final atomic number and atomic mass respectively.

²³⁵₉₂U + ¹₀n → ? + ¹³⁹₅₄Xe + 3 ¹₀n

Here atomic mass =

235 + 1 = A + 139+3 ( A -= atomic mass of ?)

A = 236 - 142

A = 94

And, atomic number would be =

92 = B + 54

B = 92 - 54

B = 38

So, the atomic number of ? will be 38 and atomic mass will be = 94

The element with 38 atomic number is = Strontium Sr

c is the answer because when something is left after something evaporates that shows the chemical change.

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8