Write the balanced chemical equation between H2SO4 and KOH in aqueous solution. This is called a neutralization reaction and will produce whater and potassium sulfate. Phases are optional. 0.650 L of 0.430 M H2SO4 is mixed with 0.600 L of 0.240 M KOH. What concentration of sulfuric acid remains after neutralization?

0.166M

Explanation:

In a neutralization, the acid, H₂SO₄, reacts with a base, KOH, to produce a salt, K₂SO₄ and water. The reaction is:

H₂SO₄ + 2KOH → K₂SO₄ + 2H₂O

To solve this problem, we need to determine moles of H2SO4 and moles of KOH that reacts to find the moles of sulfuric acid that remains after the reaction:

Moles H2SO4:

0.650L * (0.430mol /L) = 0.2795moles H2SO4

Moles KOH:

0.600L * (0.240mol / L) = 0.144 moles KOH

Moles of sulfuric acid that reacts with 0.144 moles of KOH are:

0.144 moles KOH * (1mol H2SO4 / 2 mol KOH) = 0.072 moles of H2SO4 react.

And remain:

0.2795moles H2SO4 - 0.072moles H2SO4 = 0.2075 moles of H2SO4 reamains.

In 0.650L + 0.600L = 1.25L:

Molar concentration of sulfuric acid:

0.2075 moles of H2SO4 / 1.25L =

fe 55.85 g/mol and h2o 18.02 g/mol.