Which of the elements listed below has the smallest atomic radius? Sulfur O Chlorine Oxygen Fluorine

F has the smallest atomic radius.

Explanation:

Atomic radius is one of the perIodic properties defined by the Periodic Table.

Atomich radius is the distance to the nucleus that comprises 95 % of the density  electronic load.  It can be defined  as a function of the internuclear distance. Although this distance varies, depending on whether the atoms are linked by a chemical bond or simply in contact without forming  link.

Atomic radius is a periodic property that increases by period (from the top to below) and decreases (from left to right) by group.

In the same group are O and F, so F < O

In the same group, we have S and Cl, so Cl < S

As Cl and F are in the same period, we define the atomic radius Cl > F and

S > Cl (In the same period)

The right way to order the elements are S > Cl > O > F  

Cadmium has larger atomic radius than sulfur.

Explanation:

Down a period, atomic radii decrease from left to right due to the increase in the number of protons and electrons across a period: when a proton is added the pull of the electrons towards the nucleus is larger, so the size of the atom decreases.

Hence, you can compare the elements that belong to a same period and predict that the atom with lower atomic number (number of protons) will haver larger atomic radius. With that:

Oxygen and fluorine are in the period 3, being oxygen to the left of fluorine, so oxygen is larger than fluorine.

Sulfur and chlorine are in the period 4, being sulfur to the left of chlorine, so sulfur is larger than chlorine.

Now see whan happens down a group. Atomic radius increases from top to bottom within a group due to electron shielding. That permits you to compare the size of the elements in a group:

Fluorine and chlorine are in the same group (17), with chlorine directly below fluorine, so the atomic radius of chlorine is larger than the atomic radius of fluorine.

Sulfur and oxygen are in the same group (16), with sulfur directlly below oxygen, so sulfur the atomic radius of sulfur is larger than the atocmi radius of oxygen.

So far, you can rank the atomic radius of sulfur, chlorine, fluorine, and oxygen, in increasing order as:

O < F < Cl < S, concluding that O, F, and Cl have smaller atomic radius than S.

Cadmiun, Cd, is to the left and below sulfur, so both electron shielding (down a group) and increase of the number of protons (down a period) lead to predict the cadmium has a larger atomic radius than sulfur.

the answer is 303.15 or 303

nacl or sodium chloride is an ionic compound. this is because an ionic compound pertains to a compound that consists of positively and negatively charged ions. in this case, na (sodium) has a tendency to lose one electron when it reacts with with other atoms, so the resulting sodium ion contains 11 protons and 10 electrons, thus making it positively charged (na+), when chlorine reacts, it usually gains one electron to form an ion called chloride, thus making it negatively charged ( since the ions are oppositely charged, they attract.