If 1.0 volumes of 1.0 M solutions of sodium hydroxide and lead (II) nitrate are mized how many moles of product are produced

0.5 moles of Pb(OH)₂ are produced.

Explanation:    

The reaction is:  

If we have 1.0 liter of 1.0 M of sodium hydroxide and lead (II) nitrate, the number of moles are:  

Now, we need to find the limiting reactant knowing that 2 moles of sodium hydroxide react with 1 mol of lead (II) nitrate:

Since we have 1 mol of sodium hydroxide and we need 2 moles to react with lead (II) nitrate, then the limiting reactant is sodium hydroxide.

We can find the number of moles of lead (II) hydroxide produced as follows:

Therefore, 0.5 moles of Pb(OH)₂ are produced.

I hope it helps you!  

b..

is the correct one

explanation:

covalent bonds form as valence electrons are shared between two atoms. lewis structures and structural formulas are common ways of showing the covalent bonding in organic molecules. formal charge describes the changes in the number of valence electrons as an atom becomes bonded into a molecule.

i just learnt this recently but i need to look through my notes again