Which of the following correctly shows the word equation for the reaction of aluminum and copper oxide yielding aluminum oxide and copper? A. aluminum + aluminum oxide → copper + copper oxide
B. aluminum + copper oxide → aluminum oxide + copper
C. aluminum oxide + copper → aluminum oxide + copper
D. copper + aluminum → copper oxide + aluminum oxide

The correct answer should be "electrons orbit the nucleus in circular motions exactly as shown on the classic bohr model."

Self-ionizes to form an equilibruium system in which [ h_{3} o^{+} ]=[ oh^{-} ]=10^{-7} m

Reaction involved in present system is :   c12h22o11 + h2o → 2 c6h12o6the reaction system is obeying following rate law:   rate = k[c12h22o11]thus, it is a first order reaction.now, for 1st order reactionrate constant (k) =  given: initial conc. = 3.0 g, final conc. = 2.7 g, t = 2.5 h∴rate constant (k) =  ∴ k = 0.04215 h-1now, for 1st order reaction, half life = 0.693/k = 0.693/0.04215 = 16.4 hthus correct answer is option b