4. A 40.0L tank of ammonia has a pressure of 12.7 kPa. Calculate the volume of the ammonia if its pressure is changed to 8.4 kPa while its temperature remains constant.

The volume of the ammonia gas if it's pressure is changed to 8.4 KPa is 60.5 L

From the question given above, The following data were obtained:

Initial pressure (P₁) = 12.7 KPa

Initial volume (V₁) = 40 L

Final pressure (P₂) = 8.4 KPa

Temperature = constant

Using the Boyle's law equation, the final volume of the ammonia can be obtained as illustrated below:

P₁V₁ = P₂V₂

12.7 × 40 = 8.4 × V₂

508 = 8.4 × V₂

Divide both side by 8.4

V₂ = 508 / 8.4

Therefore, the final volume of the ammonia gas is 60.5 L

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V₂ = 60.47L

Explanation:

Given data:

Initial volume = 40.0 L

Initial pressure = 12.7 KPa

Final volume = ?

Final pressure = 8.4 KPa

Solution:

The given problem will be solved through the Boyls law,

"The volume of given amount of gas is inversely proportional to its pressure by keeping the temperature and number of moles constant"

Mathematical expression:

P₁V₁ = P₂V₂

P₁ = Initial pressure

V₁ = initial volume

P₂ = final pressure

V₂ = final volume  

Now we will put the values in formula,

P₁V₁ = P₂V₂

12.7 KPa× 40.0 L = 8.4 KPa × V₂

V₂ = 12.7 KPa× 40.0 L/ 8.4 KPa

V₂ = 508 KPa. L / 8.4 KPa

V₂ = 60.47L

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