Calculate the amount in moles and grams of KMnO4 present in 3dm^3 of 0.25M

Number of moles   = 0.75 mol

Mass = 118.5 g

Explanation:

Given data:

Number of moles of KMnO₄ = ?

Mass in gram = ?

Molarity of KMnO₄ = 0.25 M

Volume of KMnO₄ solution = 3 dm³ (3 L)

Solution:

Molarity is used to describe the concentration of solution. It tells how many moles are dissolve in per litter of solution.

Formula:

Molarity = number of moles  / L of solution

0.25 M = number of moles / 3 L

Number of moles   = 0.25 M× 3 L

            M = mol/L

Number of moles   = 0.75 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.75 mol × 158 g/mol

Mass = 118.5 g

given the reactants, h2so4 and koh, we are asked to determine the product(s) of the reaction. since h2so4 is an acid and koh is a base. this is a neutralization reaction, thus, the products are salt and water. 

so, h+ from h2so4 will react with oh- from koh forming h2o. k+ will also react with so4 2- forming k2so4. therefore, the balanced reaction will be:

h2so4 + 2koh > k2so4 + 2h2o

explanation:

catya your not at all which answer i've seen you do this on another question!