If 10.28 g of Cu(NO3)2 are obtained from the reaction of 4.54 g of Cu with excess HNO3, what is the percent yield of the reaction? (show workings for full grade)

The percent yield of the reaction : 77.2%

Percent yield is the comparison of the amount of product obtained from a reaction with the amount you calculated

General formula:

Percent yield = (Actual yield / theoretical yield )x 100%

An actual yield is the amount of product actually produced by the reaction. A theoretical yield is the amount of product that you calculate from the reaction equation according to the product and reactant coefficients

Reaction

Cu + 4HNO₃ → Cu(NO₃)₂ + 2NO₂ + 2H₂O

mol of Cu(MW=63.55 g/mol) :

mol ratio Cu : Cu(NO₃)₂ = 1 : 1, so mol Cu(NO₃)₂ :

mass of Cu(NO₃)₂ (MW=187,56 g/mol) :

10.28 g of Cu(NO₃)₂ are obtained from the reaction⇒actual yield

The percent yield :

state the principle of separating two immiscible liquids by separating funnel. describe an activity with diagram to separate a mixture of water and kerosene oil. answer: immiscible layers separate out in layers depending on their densities in separating funne

some sources quote the lethal dose, for an average 170lbs opiate-naive individual is between 75 and 375 mg