A gas at STP has a volume of 1.5 L. What will the pressure be if it is at 26° C occupying .75 L

P₂ =  2.19 atm

Explanation:

Given data:

Initial volume = 1.5 L

Initial pressure =1 atm

Initial temperature = 273K

Final temperature = 26°C (26+273 = 299 K)

Final volume = 0.75 L

Final pressure = ?

Formula:  

P₁V₁/T₁ = P₂V₂/T₂  

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

P₂ = P₁V₁ T₂/ T₁ V₂  

P₂ = 1 atm × 1.5 L × 299 K / 273 K × 0.75 L  

P₂ = 448.5 atm .L. K / 204.75 K.L

P₂ =  2.19 atm

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