A 40.4 g sample of a protein contains 17.16 g of carbon, 3.17 g of hydrogen, 13.71 g of oxygen, and the rest being nitrogen. This 40.4-gram sample is known to be 0.07141 moles. Determine the molecular formula of this protein.

The molecular formula of this protein : C₁₈H₄₂O₁₂N₆Further explanation  

The empirical formula is the smallest comparison of atoms of compound forming elements.  

A molecular formula is a formula that shows the number of atomic elements that make up a compound.  

(empirical formula) n = molecular formula  

The principle of determining empirical formula and molecular formula  

Determine the mass ratio of the constituent elements of the compound.  Determine the mole ratio by dividing the elemental mass with the relative atomic mass obtained by the empirical formula  Determine molecular formulas by looking for values of n  

Find mol ratio for every component :

C (Ar=12 g/mol):

H(Ar=1 g/mol) :

O(Ar=16 g/mol) :

N (r=14 g/mol) :

Mass of Nitrogen :

40.4-(17.16+3.17+13.71)=6.36 g

N :

C : H : O : N = 1.43 : 3.17 : 0.857 : 0.454 = 3.15 : 7 : 1.89 : 1=3:7:2:1

Empirical formula : C₃H₇O₂N

Molecular mass of protein :

(C₃H₇O₂N)n=565.75

(12.3+1.7+2.16+14)n=565.75

(89)n=565.75

n=6.4≈6

so the molecular formula : C₁₈H₄₂O₁₂N₆

The answer is yes b ffgnbsfgnbnfgbnfgsnb

Temperature and pressure