Calculate the change in entropy as 0.0419 kg of ice at 273.15 K melts. The latent heat of fusion of water is 333000 J/kg .

Explanation:

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In this case, since the entropy and enthalpy are related via the following equation for any process:

As this problem relates the enthalpy and entropy of fusion, given the mass, melting temperature and heat of fusion, we compute the change in entropy of fusion as shown below:

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(newtons first law)

conservation of momentum law states :

momentum before collision = momentum after collision

momentum p (kg-m/s)= mass * velocity

say moving car=1 000 kg, velocity = 10 m/s then p = 1 000*10= 10 000 kg-m/s

say still car = 2 000 kg, velocity = 0 m/s then p = 2 000* 0 = 0 kg-m/s

total momentum prior to collision = 10 000 + 0 = 10 000 kg-m/s

momentum after collision = 10 000 kg-m/s

mass now = 1 000 kg+2 000 kg = 3 000 kg

10 000 = 3 000 kg* velocity m/s

10 000/3 000 = velocity

3.33 m/s = velocity after collision

an impulse is a force applied over time , momentum is exclusive of external forces and a perfect collision is implied