The initial temperature of a bomb calorimeter is 28.50°C. When a chemist carries out a reaction in this calorimeter, its temperature decreases to 27.45°C. If the calorimeter has a mass of 1.400 kg and a specific heat of 3.52 J/(gi°C), how much heat is absorbed by the reaction? Use q equals m C subscript p Delta T..
140 J
418 J
1,470 J
5,170 J

The correct answer is 5,170 J

Explanation:

The heat absorbed by the reaction (Qr) is equal to the heat released by the calorimeter (Qcal):

Qr = - Qcal

We calculate Qcal from the mass of the calorimeter (m), the specific heat (Cp), and the change in temperature (ΔT), as follows::

Qcal = m x Cp x ΔT

We have the following data:

m = 1.400 kg x 1000 g/1 kg = 1,400 g

Cp = 3.52 J/g°C

Initial T = 28.50°C + 273 = 301.50 K

Final T = 27.45°C + 273 = 300.45 K

ΔT = Final T - Initial T = 300.45 K - 301.50 K = -1.05 K

So, we introduce the data in the mathematical expression for Qcal:

Qcal = m x Cp x ΔT = 1,400 g x 3.52 J/g°C x (-1.05 K) = -5,174.4 J ≅ -5,170 J

Therefore, the heat absorbed by the reaction is:

Qr = - Qcal = -(-5,170 J) = 5,170 J

any far is the region can control the climate

answer: e.   sour taste

explanation: acids are those substances which dissociates in water to give ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. acids are sour in taste. example: hcl

bases are those substances which dissociates in water to give ions or accepts ions. as they dissociate to give ions, they act as electrolytes and thus are electrically conductive. bases are bitter in taste. bases are slippery in nature.