What's the balanced equation for Iron and copper (II) sulfate solution.

 2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

Explanation:

The reactants are:

   Iron  = Fe

  Copper (II) sulfate solution = CuSO₄

The reaction is given as:

            Fe +  CuSO₄  →  Fe₂(SO₄)₃   +  Cu

This is a single displacement reaction;

  Now let us balance the equation;

             aFe +  bCuSO₄  →  cFe₂(SO₄)₃   +  dCu

Conserving Fe;

                       a  = 2c

  Conserving  Cu;

                      b  = d

  Conserving S;

                      b  = 3c

  Conserving O;

                    4b  = 12c  

let b  = 1;

    c =  

     d  = 1

     a  =

Multiply through by 3 to get whole numbers;

  a  = 2, b = 3, c  = 1 and d  = 3

           2Fe +  3CuSO₄  →  Fe₂(SO₄)₃   +  3Cu

fe 55.85 g/mol and h2o 18.02 g/mol.