If you exposed a plant to C14O218, and flashed a light on it for a short period, in which products would you expect to see the label in a few minutes?a. the C14 would be in Glyceraldehyde 3-Phosphate, and the O18 would be molecular Oxygenb. The C14 would be released as CO2, and the O18 would appear in H2Oc. The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule. d. The C14would appear in Ribulose bis Phosphate, and the O18 would be released as molecular Oxygene. None of the above

The C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule

Explanation:

Isotopic labeling is a common method for deducing reaction mechanism in chemistry.

In photosynthesis, the oxygen in the found in Glyceraldehyde-3-Phosphate comes from the carbon dioxide, This is also finally found in the glucose produced at the end of the cycle.

The oxygen in water is released into the atmosphere as the oxygen molecule.

Therefore, the C14 would be found in Glyceraldehyde-3-Phosphate, and the O18 would also be found in the same molecule.

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

explanation:

let the different atoms be x and y. each with four protons and same mass will be represented as follows.

mass number is number of protons + number of neutrons.

            and  

since, it is given that one has a negative charge while the other is neutral. therefore, there will be increase in number of protons and the atom will be represented as follows.

according to periodic table, mass number of beryllium is 9 and it has atomic number 4 so, the atoms will be and .  

the protons and neutrons will be located inside the nucleus whereas the electrons will be revolving around the nucleus.