Please answer Question 4(5 points)
If 2.0 moles of water is cooled from 101 degree C steam to -1.0 degree Cice, what is the total energy lost?

Q = -15363.65 J

Explanation:

Given data:

Number of moles of water = 2.0 mol

Initial temperature = 101°C

Final temperature = -1.0°C

Total energy lost = ?

Solution:

Mass of water:

Mass = number of moles × molar mass

Mass = 2 mol × 18 g/mol

Mass = 36 g

Heat lost:

specific heat capacity of water is 4.184 J/g.°C

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT =  -1.0°C -  101°C

ΔT =  -102°C

Q = 36 g × 4.184 J/g.°C × -102°C

Q = -15363.65 J

Negative sign show heat is released.

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