When nitrogen gas (N2) reacts with hydrogen gas(H) ammonia gas (NH3) is formed. How many grams of hydrogen gas are required to react completely with 3.5 L of nitrogen at STP? Show your work for full credit.

Mass of Hydrogen gas required to react : 0.936 g

Reaction on Nitrogen gas and Hydrogen gas to produce Ammonia gas

N₂ (g) + 3 H₂ (g) ⇒ 2 NH₃ (g)

Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol

so mol Nitrogen for 3.5 L at STP :

From the equation, mol ratio of N₂ : H₂ = 1 : 3, so mol H₂ :

then mass of Hydrogen(MW= 2 g/mol) :

atomic mass = 39

number of neutrons = 20

number of protons= 19

electronic configuration = 1s2 2s2 2p6 3s2 3p6 4s1

the number of electron in first shell = 2

number of electrons in n=3 shell = 8