A 1000-g iron frying pan is placed on a stove. The pan increases from 20°C to 130°C. If the specific heat of iron is 0.444 J/goC, how much heat was gained by the pan? A. -48,840 J
B. 48,840 J
C. 57,720 J
D. - 57,720 J

48,840 J

Explanation:

First of all, you can use process of elimination to take out the negatives, since you can't gain negative heat (in this situation).

Now just for the Math:

Remember this equation — Q = mcΔt

The variables for the equation are:

— m - The measure in grams or kilograms.

— c - The measure of the specific heat.

— Δt - The measure the change in temperature.

Now find these variables:

— m = 1000 g

— c = 0.444 J/goC

— Δt = 130 - 20 = 110 C

Now plug these numbers into the equation and solve!

Q = mcΔt

If you multiply the number you would get 48,840 J. You also have to cancel out the units as well.

Hope it Helped!

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the answer is na (sodium)