Estimate the heat of neutralization of h3po4 in kj/mol given these data: heat transferred = 2.5 x 102 j moles of h3po4 = 1.4 x 10−3 mol moles of naoh = 5.0 x 10−3 mol

Below are the steps to get the answers:

1.) write out the balance equation 3NaOh+H3PO4->Na3PO4+3H2O
 
2.) You are given everything needed to calculate q=heat transfer=2.2*10^2, H3PO4 moles= 1.5*10^-3, NaOH moles=5.0*10^-3
 
3.) equation is deltaHneutraliztion=q/Moles of limiting reagent H3PO4 is limiting reagent because lowest moles, and is used up first
 
4.) Now plug in variables DeltaH=2.2*10^2(1.5*10^3)= 146.67kj/mole Notice we had to convert J to kj,

What’s the solution?