How many grams of solid lithium hydroxide must be used to prepare 450
mL of 0.55M LiOH solution?

Mass = 6.706 g

Explanation:

Given data:

Mass of lithium hydroxide = ?

Volume of lithium hydroxide = 450 mL (450/1000 = 0.450 L)

Molarity of lithium hydroxide = 0.55 M

Solution:

Formula:

Molarity = number of moles / volume in L

0.55 M = number of moles / 0.450 L

Number of moles = 0.55 M × 0.450 L

Number of moles = 0.25 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 0.25 mol × 23.95 g/mol

Mass = 6.706 g

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i believe you are right for all except the 3rd ( look at sqdancefan his answer is much better)