Which arrow represents water forming outside a cold water bottle left outside

The phase transition that represent the the cooling of gaseous water to form liquid outside a bottle left outside which is a process known as is represented by the arrow 2

Explanation:

The different phase transitions that occur in mater are;

1) A phase transition from the solid phase to the liquid phase which occur by heating, represented by the arrow 2 and the process is known as melting

2)  A phase transition from the liquid phase to the gaseous phase which occur by further heating the liquid, represented by the arrow 1 and the process is known as evaporation

3) A phase transition from the gaseous phase to the liquid phase which occur by cooling the hot gas, represented by the arrow 2 and is known as condensation

4) A phase transition from the liquid phase to the solid phase which occur by further cooling the liquid, represented by the arrow 5 and the process is known as freezing

5) A phase transition from the solid phase to the gaseous phase which occur by heating the cold solid, represented by the arrow 3 and the process is known as sublimation

6) A phase transition from the gaseous phase to the solid phase which occur by cooling the gas, represented by the arrow 6

Therefore, the phase transition that represent the the cooling of gaseous water to form liquid outside a bottle left outside is represented by the arrow 2

answer: - 3.) the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

solution: - as per the rules, oxidation number of oxygen in its compounds is -2. the sum of oxidation numbers of all the elements of a molecule or compound is zero.

also, the oxidation number in elemental form is zero.

in no, the oxidation number of o is -2 so the oxidation number of n is +2 so that the sum is zero.

similarly, the oxidation number of c in co is +2 and o is -2.

on product side the oxidation number of n is 0 as it is in the elemental form() .

oxidation number of c in carbon dioxide is +4 as there are two oxygen in it and we know that each oxygen is -2.

so, oxidation number of n is changing from +2 to 0 and the oxidation number of c is changing from +2 to +4.

since nitrogen is reduced and hence no is acting as an oxidizing agent. carbon is oxidized and so co is acting as a reducing agent.

so, the right choice is number 3.)the oxidation state of nitrogen in no changes from +2 to 0, and the oxidation state of carbon in co changes from +2 to +4 as the reaction proceeds.

it would be a gas formation