How many grams of Kr are in a 9.59 L cylinder at 46.0 'C and 4.62 atm?
mass:

Mass = 141.6 g

Explanation:

Given data:

Mass of Kr in gram =  ?

Volume in L = 9.59 L

Temperature = 46.0°C

Pressure = 4.62 atm

Solution:

The given problem will be solve by using general gas equation,

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

46.0+273 = 319 K

4.62 atm × 9.59 L = n× 0.0821 atm.L/ mol.K  ×319 K

44.3 atm.L = n×26.19 atm.L/ mol

n = 44.3 atm.L / 26.19 atm.L/ mol

n = 1.69 mol

Mass in gram:

Mass = number of moles × molar mass

Mass = 1.69 mol × 83.79 g/mol

Mass = 141.6 g