How many phosphorus atoms are in two moles of the compound Mg3(PO4)2? O 4 atoms O 1.2 x 1023 O 2 atoms O 2.4 x 1023

The number of phosphorus atoms : 2.408 x 10²⁴

The mole is the number of particles(molecules, atoms, ions) contained in a substance  

1 mol = 6.02.10²³ particles

Can be formulated

N=n x No

N = number of particles

n = mol

No = Avogadro's = 6.02.10²³

moles of Mg₃(PO₄)₂ = 2

moles of phosphorous(P) atoms in Mg₃(PO₄)₂ ⇒ mol ratio of elements in the compound(for P=2)

The number of atoms of  phosphorous(P) :

ill try to . no promises tho.

explanation: