Given the information A+BC⟶2D⟶DΔ∘Δ∘=626.2 kJΔ∘=371.0 J/K=549.0 kJΔ∘=−184.0 J/K calculate Δ∘ at 298 K for the reaction A+B⟶2C Δ∘=
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Answerlimiting reactant;

Pcl5 + 4 h2o = h3po4 + 5 hclthe ratio is 1: 5 for  pcl  and hcl, 1 mole of pcl produces 5 moles of hclmolecular weight of pcl5 is: 31 + (5 x 35.5) = 208.5above we have 75.5 / 208.5 = 0.36 moles so this will produce0.36 x 5 = 1.81 moles of hcl.