What mass of carbon monoxide gas (CO) would occupy a volume of 4.30 L at STP? Explain how you got the answer.

5.38 g of CO.

Explanation:

From the question given above, the following data were obtained:

Volume of CO = 4.3 L

Mass of CO =?

Next, we shall determine the number of mole of CO that occupied 4.3 L at STP. This can be obtained as follow:

Recall = 1 mole of any gas occupy 22.4 L at STP.

1 mole of CO occupied 22.4 L at STP.

Therefore, Xmol of CO will occupy 4.3 L at STP i.e

Xmol of CO = 4.3 / 22.4

Xmol of CO = 0.192 mole.

Thus, 0.192 mole of CO occupy 4.3 L at STP.

Finally, we shall determine the mass of CO as follow:

Mole of CO = 0.192 mole.

Molar mass of CO = 12 + 16 = 28 g/mol

Mass of CO =?

Mole = mass /Molar mass

0.192 = mass of CO / 28

Cross multiply

Mass of CO = 0.192 × 28

Mass of CO = 5.38 g.

Therefore, 5.38 g of CO occupied 4.3 L at STP.