What is the molarity of an aqueous solution that contains 12.2 grams of srcl2 dissolved in 2,500 milliliters of solution?

Molar mass SrCl₂ = 158.53 g/mol

number of moles:

mass SrCl₂ / molar mass

12.2 / 158.53 => 0.0769 moles

2,500 mL in liters: 2,500 / 1000 => 2.5 L

Therefore:

M = moles / volume

M = 0.0769 / 2.5

M = 0.03076 mol/L⁻¹