A gas sample occupies 4.39 L at 44 ºC. What will be the new volume, using Charles’ Law, if the temperature decreases to 25 ºC?

Hi there! :)

Use the proportion for Charles' Law where:

v1 = initial volume

t1 = initial temperature

v2 = final volume

v2 = final temperature

Substitute in the given values into the proportion:

v1 = 4.39 L

t1 = 44° C

t2 = 25°C

v2 = x L

Set up the proportion:

Cross multiply:

The new volume will be approximately 2.49 L.

Explanation:

We are given that a gas sample occupies 4.39 L at 44° C.

We are also given that we are going decrease the temperature to 25° C.

Charles' Law has a formula which shows the relationship between the volumes of a samples and the temperatures of the samples.

The proportion is shown as:

,

where V₁ and V₂ are the initial and final volume respectively and T₁ and T₂ are the initial and final temperature respectively.

This proportion can be used to determine what our unknown is. We need to know the final volume.

Therefore, if we reduce the temperature to 25 °C, we will be reducing the volume of the substance to 2.49 L.

while cooking a piece of 1/2 pound beef steak, a cast iron pan (2.4kg in weight) was heated 260 celsius.

the objects have the same charge.