According to the following reaction, how much energy is evolved during the reaction of 72.5 g Cl2?  (Assume that B2H6 is present in excess)             B2H6 (g) + 6 Cl2 (g)  →  2 BCl3 (g) + 6 HCl (g)         ΔH°rxn = -1396 kJ

Ch4 is nonpolar and insoluble in water. since all of the hydrogen atoms are evenly spread around the carbon atom even through the c h bond is polar all the poles cancel each other out.

Sorry i dont understand the question can you rephase it?

Is there any options, for this

First up write the aim
then write the materials reqd.
then the procedure which you follow
then observation
then conclusion
then you can write lab safety rules or precautions(you can avoid if u want).
lemme' give an example
aim: to observe the double displacement reaction
materials reqd: bacl2 and na2so4, test tubes and a dropper
procedure:
1. take bacl2 in a test tube and na2so4 in the other.
2. then pour bacl2 into na2so4 solution.
3. observe
observation:
you will see that a white precipitate is formed called baso4. along with that common salt or nacl is formed.
the equation is
bacl2+na2so4=baso4+2nacl
conclusion:
a double displacement reaction is observed.
hope it