Given the following equation: 2 KClO3 → 2 KCI + 3 02. How many liters of oxygen are produced by reacting 12.0 moles of KCIO3

403.2 L of O2

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

2KClO3 —> 2KCI + 3O2

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Next, we shall determine the number of mole of O2 produced by the decomposition of 12 moles of KClO3. This can be obtained as follow:

From the balanced equation above,

2 moles of KClO3 decomposed to produce 3 moles of O2.

Therefore, 12 moles of KClO3 will decompose to produce = (12 × 3)/2 = 18 moles of O2.

Thus, 18 moles of O2 is produced.

Finally, we shall determine the volume of O2 produced from the reaction. This can be obtained as illustrated below:

Recall: 1 mole of any gas occupy 22.4 L at STP.

1 mole of O2 occupies 22.4 L at STP.

Therefore, 18 moles of O2 will occupy = 18 × 22.4 = 403.2 L at STP.

Thus, 403.2 L of O2 is produced from the reaction.