a sample of compound determined to contain 1.71 g C and 0.287 g H. The corresponding empirical formula is

The empirical formula is .

Explanation:

Mass of C = 1.71 g

Mass of H = 0.287 g

Step 1 : convert given masses into moles.

Moles of C =

Moles of H =

Step 2 : For the mole ratio, divide each value of moles by the smallest number of moles calculated.

For C =

For H =

The ratio of C: H = 1: 2

Hence the empirical formula is .

2b2t

explanation:

2b2t