Which substance is the limiting reactant when 18 g of sulfur reacts with 30 g of oxygen and 36 g of potassium hydroxide according to the following chemical equation?
2 S(s) + 3 O2(g) + 4 KOH(aq) - 2 K2SO4(aq) + 2 H2O(1)

O KOH(aq)
O2(g)
O K2SO4
O S(s)
O None of these substances is the limiting reactant.

120,630,890

step-by-step explanation:

110+10=120,620+10=630,880+10=890

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2