What mass of Sodium Iodide (NaI) will react with 7.82 grams of Chlorine (Cl2)? 2NaI + Cl2 > 2NaCl + I2

16.49g

Explanation:

Given parameters:

Mass of Chlorine gas = 7.82g

Unknown:

Mass of NaI  = ?

Solution:

The reaction equation is given as:

            2NaI  + Cl₂  →  2NaCl + I₂  

To solve this problem, find the number of moles of the known specie first;

 Number of moles of Cl₂  =  

   Molar mass of Cl₂   = 2(35.5)  = 71g/mol

  Number of moles =   = 0.11mole

From the balanced reaction equation;

            2 mole of Cl₂ will react with 2 mole of NaI

          0.11 mole of Cl₂ will also react with 0.11mole of NaI

Mass of NaI  = number of moles x molar mass

  Molar mass of NaI  = 23 + 126.9  = 149.9g/mol

Mass of NaI  = 0.11 x 149.9 = 16.49g