A compound has a molecular mass of 54 and an empirical formula of C2H3. What is the molecular formula of the compound?

C₄H₆

Explanation:

The empirical formula of the compound is given as;

       C₂H₃

Now find the molecular mass of the empirical formula first;

  C₂H₃  =  2(12) + 3(1) = 27g/mol

Since the molecular mass of the true compound is 54,

  Ratio of the molecular formula to empirical formula  = 54/27  = 2

Molecular formula  = 2(  C₂H₃ )  = C₄H₆

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