Calculate the number of moles in 32.5 g of Mg(NO3)2.

n = 0.219 moles

Explanation:

Given mass, m = 32.5 g

Molar mass of Mg(NO₃)₂ is :

M = 1 × 24 + 2× 14 + 6 × 16

M = 148 g/mol

Let there are n number of moles. It is equal to given mass divided by molar mass.

Hence, there are 0.219 moles in 32.5 g of Mg(NO₃)₂.

am i too late?

explanation:

thats how its supposed to be